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36x^2+33x-210=0
a = 36; b = 33; c = -210;
Δ = b2-4ac
Δ = 332-4·36·(-210)
Δ = 31329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{31329}=177$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-177}{2*36}=\frac{-210}{72} =-2+11/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+177}{2*36}=\frac{144}{72} =2 $
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